Question 1098949
{{{ log(p) - log(q) = 2*log(r) }}}
{{{ log( p/q ) = log( r^2 ) }}}
{{{ p/q = r^2 }}}
{{{ p = q*r^2 }}}
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check:
suppose {{{ q = 1000 }}} and
{{{ r = 100 }}}
then {{{ p = q*r^2 }}}
{{{ p = 10^3*10^4 }}}
{{{ p = 10^7 }}}
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{{{ log( p ) - log( 1000 ) = 2*log( 100 ) }}}
{{{ log(p ) - 3 = 2*2 }}}
{{{ log(p) = 7 }}}
{{{ p = 10^7 }}}
OK