Question 1098866
{{{f(x)=a(x-1/2)(x+3)^2}}}
So when {{{x=1}}},
{{{f(1)=a(1-1/2)(1+3)^2=24}}}
{{{a(1/2)(4)^2=24}}}
{{{a=48/16}}}
{{{a=3}}}
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{{{f(x)=3(x-1/2)(x+3)^2}}}
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