Question 1098832
Five years ago,
{{{K-5=3(D-5)}}}
{{{K-5=3D-15}}}
1.{{{K-3D=-10}}}
Five years from now,
{{{K+5=2(D+5)}}}
{{{K+5=2D+10}}}
2.{{{K-2D=5}}}
Subtract 2 from 1,
{{{K-3D-K+2D=-10-5}}}
{{{-D=-15}}}
{{{D=15}}}
Now use either equation to solve for K.