Question 97994
{{{(3x^-3)(x^6)/y^-2}}}
I believe this to be the actual problem?
Negative exponents turn integers into fractions, and if they are already in the denominator they are flipped into the numerator.
{{{(x^6)(y^2)/3x^3}}}
Now you cancel the x's, you have six in the numerator and 3 in the denominator,
{{{(xxxxxx)(y^2)/3xxx}}}
cancel out three, and you are left with;
{{{x^3y^2/3}}}
:)