Question 1098577
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Let *[tex \Large x] represent "the number".


Then *[tex \Large \frac{3x}{4}] is 3/4 of the number, and *[tex \Large \frac{5x}{12}] is 5/12 of the number.  Since 3/4 is more than 1/2 and 5/12 is less than 1/2, 5/12 must be less than 3/4 and the positive difference must be *[tex \Large \frac{3x}{4}\ -\ \frac{5x}{12}].


7 less than 5/6 of the number is *[tex \Large \frac{5x}{6}\ -\ 7].  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x}{4}\ -\ \frac{5x}{12}\ =\ \frac{5x}{6}\ -\ 7]


Solve for *[tex \Large x]. Hint: Nothing in the problem restricts *[tex \Large x] to the set of integers.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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