Question 97894
Let x=number of pounds of nuts that cost $1.10 per pound
Value of these nuts=$1.10x
Then 50-x=number of pounds of nuts that cost $1.80 per pound
Value of these nuts =$1.80(50-x)

Value of final mixture = $1.30(50)

Now we know that the value of the nuts before they are mixed ($1.10x+$1.80(50-x)) is equal to the value of the nuts after they are mixed($1.30*50).  So our equation to solve is:

$1.10x+$1.80(50-x)=$1.30*50 get rid of parens

$1.10x+$90-$1.80x=$65  subtract $90 from both sides

$1.10x+$90-$90-$1.80x=$65-$90  combine like terms
-$0.70x=-$25  divide both sides by -$0.70

x=35.714 lbs of nuts that cost $1.10 per pound

CK

(35.714)($1.10)+($1.80)(50-35.714)=$1.30*50

39.2854+25.714=65
65.002~65


Hope this helps---ptaylor