Question 1098458
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<pre>
{{{log(3,(n^2-3n+5))}}} = 2   <=== equivalently ===>

n^2 - 3n + 5 = 3^2 = 9  <=== equivalently ===>

n^2 - 3n - 4 = 0  =====>  factor left side  <=== equivalently ===>

(n-4)*(n+1) = 0  <=== equivalently ===>


The roots of the last equation are 4 and -1.


<U>Check</U> .  <U>THERE IS NO NEED TO CHECK</U>  <U>since all transformations were equivalent</U> (!).
</pre>

Solved.