<PRE><B>Question 1098438</B>
1. There is no question. Were you expected to re-write it as an equivalent expression?
{{{(2a^4b)^3=2^3(a^4)^3b^3=8a^(4*3)b^3=8a^12b^3}}}
 
2. The y-intercept is the point (or the y-coordinate of the point)
where the line intersects the y-axis,
which is the line where {{{x=0}}} .
So, substituting 0 for x,
{{{0-4y=12}}} --&gt; {{{-4y=12}}} --&gt; {{{y=12/(-4)}}} --&gt; {{{y=-4}}} .
 
3. {{{sqrt(12)+sqrt(27)=sqrt(4*3)+sqrt(9*3)=sqrt(4)*sqrt(3)+sqrt(9)*sqrt(3)=2sqrt(3)+3sqrt(3)=(2+3)sqrt(3)=5sqrt(3) }}}
 
4. Longer of the factors of {{{3x^2+x}}} is {{{x}}} .
{{{3x^2=3*x*x}}} or {{{(3x)*x}}} ,
and {{{x=1*x}}} , so {{{x}}} is a common factor, and {{{3x^2+x=x(3x+1)}}} .
 
5. One of the factors of {{{x^2-9}}} is {{{x-3}}} ,
and another factor of {{{x^2-9}}} is {{{x+3}}} .
{{{x^2-9=(x-3)*(x+3)}}}
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