Question 1098316
<br>Let a be the first term and d be the common difference.<br>
If the sum of the first 10 terms of an arithmetic sequence is 910, then that sum of 910 is the sum of 5 pairs of numbers, each with a sum of 910/5 = 182. One of those pairs is the sum of the first and tenth numbers.<br>
The first number is a; the 10th number is a+9d: so
{{{a + a+9d = 182}}}
{{{2a+9d = 182}}}<br>
The 20th term, 95, is a+19d:
{{{a+19d = 95}}}<br>
That gives you two equations in a and d which you can solve to find the answer to the problem.<br>
But I'm wondering if you have shown the right numbers, because with the numbers you show, the terms of the sequence turn out to be ugly fractions.<br>
So I'm not going to show the ugly arithmetic; you can solve the pair of equations on your own.