Question 1098165
<br>The response from tutor ikleyn is fine, although she doesn't take you all the way to the answer.  But with her obvious start, I would definitely go a different direction than she does to get the answer.<br>
She shows the two equations that come directly from the information given in the problem:<br>
{{{F + B = 375}}}          (1)    (counting seats)
{{{25*F + 21*B = 8875}}}   (2)    (counting money)<br>
But then she shows solving the system using substitution.  When the two equations are both in this form (as they often are in this kind of problem), solving the system by elimination is (for me, at least) MUCH easier:<br>
{{{25F + 25B = 9375}}}  [multiplying the first equation by 25, to make the coefficients of F the same in the two equations]
{{{25F + 21B = 8875}}}
{{{4B = 500}}}
{{{B = 125}}}<br>
125 balcony seats were sold, which means 250 floor seats.<br>
Now here is precisely the way I solve this problem:<br>
I first think "what would the total ticket cost be if all 375 seats were floor seats, and how does that compare with the actual total?"  The answer is $25*375 = $9375, which is $500 more than the actual ticket sales amount.<br>
Then I think "each balcony seat costs $4 less than a floor seat.  Therefore the number of balcony seats is $500/$4 = 125."<br>
If you look at those calculations, they are EXACTLY the calculations shown in my formal algebraic solution shown above.