Question 1097884
x + y = 31
(2/3)x = (5/8)y

16x = 15y

x + y = 31 -------(1)
16x – 15y = 0------(2)

Multiply equation (1) by 16

16x + 16y = (31)(16)
16x – 15y = 0

Subtract the two equation 

31y = 31(16)

Y = 16

Input y = 16 in equation (1)

x + y = 31

x= 31 – y = 31 – 16 = 15

Thus x = 15 and y = 16

Therefore the two values are 15 and 16