Question 1097847
This is my problem: A two-digit counting number has a value that is 8 times the sum of its digits. If 6 times the units' digit is 5 more than the tens' digit, what is the number? My math book has not given me an example of this variation of kind of problem, and I can't find one on YouTube. Can you help me learn to solve this? Walk me through the different steps? Thank you for your time!
<pre>The only sentence you need in order to figure this out is this, "A two-digit counting number has a value that is 8 times the sum of its digits." Nothing else!!

Let the tens and units digits be T and U, respectively
Then the number is: 10T + U, and we get: 10T + U = 8(T + U)
10T + U = 8T + 8U
10T - 8T = 8U - U
2T = 7U <====== This means that T = 7, and U = 2, as these are the only 2 DIGITS that satisfy this equation.
Hence, the number is: {{{highlight_green(72)}}}. That's it!!