Question 97919
{{{xy+xz = yx+yz = 2)}}}
{{{cross(xy) + xz = cross(xy) + yz}}}
{{{xz = yz}}}
{{{x = y}}}

{{{xz + yz = xy + xz = 2}}}
{{{cross(xz) + yz = xy + cross(xz)}}}
{{{yz = xy}}}
{{{z = x}}}

(with y and z different from 0)

Substitute for y and z in equation 1:
{{{2x^2 = 2}}}
{{{x^2 = 1}}}
{{{x = 1}}} or {{{x = -1}}}

x = y = z = +-1