Question 1097642
x/6+y/2+z/6=1/2
x+y+z=5
x/3+y/2+z/6=1
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x+3y+z=3
x+y+z=5
2x+3y+z=6
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-x-3y-z=-3
2x+3y+z=6
x=3
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6+3y+z=6; 3y+z=0,z=-3y
3+y-3y=5
3-2y=5
y=-1
(3, -1, 3)
Check
(1/2)-(1/2)+3/6=1/2 TRUE
3-1+3=5, TRUE
1+(-1/2)+(1/2)=1 TRUE