Question 1097758
let T represent the price of one table.
let C represent the price of 1 chair.


2T + 3C = 3500
3T + 2C = 4000


multiply both sides of the first equation by 3 and multiply both sides of the second equation by 2 to get:


6T + 9C = 10500
6T + 4C = 8000


subtract the second equation from the first to get:


5C = 2500


solve for C to get C = 500.


use either one of the original equations and replace C with 500 and solve for T.


first original equation is 2T + 3C = 3500
replace C with 500 to get 2T + 1500 = 3500
subtract 1500 from both sides of this equation to get 2T = 2000
solve for T to get T = 1000


you have T = 1000 and C = 500.


go back to the original equations and evaluate to determine if the solution is correct.


2T + 3C = 3500 becomes 2*1000 + 3*500 = 3500 which becomes 2000 + 1500 = 3500 which becomes 3500 = 3500 which confirms the solution is correct for the first equation.


3T + 2C = 4000 becomes 3*1000 + 2*500 = 4000 which becomes 3000 + 1000 = 4000 which becomes 4000 = 4000 which confirms the solution is correct for the second equation.


the price of one table is rs 1000.