Question 1097746
we have a hypotenuse as sqrt(19) and one leg of 3.


by pythagorus, c^2 = a^2 + b^2, where:


c is the hypotenuse of the right triangle.
a and b are legs of the right triangle.


therefore sqrt(19)^2 = 3^2 + x^2, where x represents one of the legs.


it doesn't matter what name you use as long as you know what the name represents.


simplify the equation to get 19 = 9 + x^2


solve for x^2 to get x^2 = 10


solve for x to get x = sqrt(10).


one leg is 3
one leg is sqrt(10).
the hypotenuse is sqrt(19).


c^2 = a^2 + b^2 becomes sqrt(19)^2 = 3^2 + sqrt(10)^2 which becomes 19 = 9 + 10 which becomes 19 = 19 which confirms the value of the other leg is sqrt(10).