Question 1097546
Triangle XYZ jas horizontal side XY, with length {{{10-0=10}}} ,
and vertical side XZ, with length {{{6-0=6}}} , perpendiculer to XY.
{{{drawing(400,300,-1,11,-1,8,grid(1),
red(line(0,6,10,0)),locate(0.1,6.5,Z),
locate(10.1,0.5,Y),locate(0.1,0,X) )}}}
If triangle MYP is similar to XYZ,
the side of MYP corresponding to side XY in XYZ is MY,
with length {{{10-5=5}}} , half the length of XY.
Then, side MP, corresponding to side XZ, would be perpendicular to MY
(a vertical side), with length {{{6/2=3}}} , half the length of XZ.
If both triangles were named clockwise,
the third vertex of MYP is {{{P(5,3)}}} .
{{{drawing(400,300,-1,11,-1,8,grid(1),
blue(line(5,3,10,0)),blue(line(5,3,5,0)),
blue(line(5,0,10,0)),locate(5.1,3.5,P),
locate(10.1,0.5,Y),locate(5.1,0,M) )}}}
 
I have no way of knowing anything about points A, C, and U,
or triangles MAP and CUZ.