Question 1097566
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In the first case, the rate of work of one single worker is {{{6/(10*5)}}} of the room per hour per worker


In the second case, the rate of work of one single worker is {{{4/(3*x)}}} of the room per hour per worker.

    (where x is unknown number of workers).


The rates are the same, which gives you an equation


{{{6/(10*5)}}} = {{{4/(3*x)}}}.


Solve for x:   x = {{{(10*4*5)/(6*3)}}} = {{{200/18}}} = {{{11}}}{{{2/18}}} hours = {{{11}}}{{{1/9}}} hours.
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See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-problem.lesson>Rate of work problems</A> 

in this site.