Question 1097509
{{{g(x)=(x+1)/(x+2)}}}

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{{{(y+1)/(y+2)=x}}}


{{{y+1=x(y+2)}}}

{{{y+1=xy+2x}}}

{{{y-xy=2x-1}}}

{{{y(1-x)=2x-1}}}

{{{y=(2x-1)/(1-x)}}}

{{{g^-1(x)=(2x-1)/(1-x)}}}