Question 97741
A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pounds of $4 per pound coffee to obtain a blend that will sell for $5? 
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Let x = amt of $8 coffee required
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It says it will be mixed with 20 lb of $4 coffee, therefore:
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Resulting amt = (x+20)
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Simple equation:
4(20) + 8x = 5(x+20)
:
80 + 8x = 5x + 100
:
8x - 5x = 100 - 80
:
3x = 20
:
x = 20/3
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x = 6{{{2/3}}} lb of $8 coffee required
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"How much of the $5 per pound coffee is there to sell?"
20 + 6{{{2/3}}} = 26{{{2/3}}} lb of $5 coffee to sell
:
:
Check solution:
4(20) + 8(6{{{2/3}}}) = 5(26{{{2/3}}})
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Using a calculator
80 + 53.3333 = 133.3333, proves our solution
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Did this make sense to you?