Question 1097337
let u=p-5
This is now 6u^2+11u+3
=(3u+1)(2u+3),
which is (3(p-5)+1)(2(p-5)+3)
(3p-14)(2p-7)
Check
The last is 6p^2-49p+98
The original is 6p^2-60p+150+11p-52
That is 6p^2-49p+98