Question 1097318
{{{T=k/R^2}}}
so,
{{{k=TR^2}}}
and
{{{T[1]R{1]^2=T[2]R[2]^2}}}
{{{8*3^2=T[2]4^2}}}
{{{T[2]=(8*9)/16}}}{{{min}}}
Simplify.