Question 1097322
y=x^2-3x+2=(x-2)(x-1)
when y =0, x-2=0, x=2; x-1=0, x=1
the two x-intercepts are at (1, 0) and (2, 0)
{{{graph(300,300,-3,3,-10,10,x^2-3x+2)}}}