Question 14207
x=4y-10
5x+3y=-4

You want to use substitution to solve this.
We already have an answer for x (only the begin, not our final answer).
This is only to start the problem,
5(4y-10)+3y=-4
Distribute the 5;
20y-50+3y=-4
Add like terms;
20y+3y-50=-4
23y-50=-4
Add 50 to both sides;
23y-50+50=-4+50
23y=46
Divide both sides by 23;
{{{23y/23=46/23}}}
y=2
Now we have what y =, so now we go back to either equation and plug in 2 for y, and figure out x.
5x+3(2)=-4
5x+6=-4
Subtract 6 from both sides;
5x+6-6=-4-6
5x=-10
Divide both sides by 5;
{{{5x/5=-10/5}}}
x=-2
So we end with;
x=-2
y=2
Hope you understand
=)