Question 1097279
2, side length of each square removed from corners
w, width of uncut tin
L, length of uncut tin


{{{system(2(w-2*2)(L-2*2)=224,wL=216)}}}



{{{(w-4)(L-4)=112}}}
{{{wL-4L-4w+16=112}}}
{{{-4L-4w+16-112+wL=0}}}
{{{-4(L+w)+16-112+216=0}}}, substituted for 216=wL;
{{{-4(L+w)+120=0}}}
{{{L+w-30=0}}}
Substitute for L;
{{{216/w+w-30=0}}}
{{{(216+w^2-30w)/w=0}}}

{{{(w^2-30w+216)/w=0}}}

The numerator must be 0.

{{{highlight_green((w-12)(w-18)=0)}}}


Tin's original dimensions are 12 and 18 inch each.