Question 1097117
4/(1+i) = 4(1-i)/((1+i)(1-i)) = (4 - 4i)/(1 - i^2) = (4 - 4i)/2 = 2 - 2i
So we have sqrt(z) = 2 - 2i + 7 - 2i = 9 - 4i
Now square both sides:
z = (9-4i)^2 = 81 - 72i + 16i^2 = 81 - 16 - 72i = 65 - 72i
Ans: z = 65 - 72i