Question 1097060
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<pre>
This system has no solution in only one case:


     If the coefficients of the second equation are proportional to coefficients of the first equation,
     BUT the right hand side terms ARE NOT proportional with that coefficient of proportionality.


     It is the same case when the straight lines of the equations are parallel,
     BUT not coincide.


The second equation coefficient "2" at "x" is 6 times the coefficient 1/3 at "x" in the first equation,
so the coefficient of proportionality must be 6:  {{{(1/3)*6}}} = 2.


Then {{{-3/2}}} becomes  {{{(-3/2)*6}}} = -9.


So, "b" must be equal 9.


Notice that the right side term 20 IS NOT 6 times 4.


Therefore,  b = 9 is the only value when the system HAS NO solution.
</pre>


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See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/coordinate/lessons/Geom-interpret-of-the-lin-system-of-two-eqns-with-two-unknowns.lesson>Geometric interpretation of the linear system of two equations in two unknowns</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I

https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.