<PRE><B>Question 1097000</B>
From 4 men and 2 women. 3 persons are chosen at random to form a committee. find the probability that the committee consists of at least one person on either sex.
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# of ways to have:
1 woman and 2 men:: 2*4C2 = 2*6 = 12
2 woman and 1 man:: 1*4 = 4
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# of random sets of 3: 6C3 = (6*5*4)/(1*2*3) = 20
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Answer::(12+4)/20 = 16/20 = 4/5
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Cheers,
Stan H.
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