Question 1096928
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line k1 y=-3/4x+2 line k2 y=4/3x+5 dont know how to graph it
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k1
{{{y=-(3/4)x+2}}}
point on line is (0,2) and slope is {{{-3/4}}}.


k2
{{{y=(4/3)x+5}}}
point on line is (0,5) and slope is {{{4/3}}}.


The two equations are given in slope-intercept form.
k1 and k2 are perpendicular.


Start with their  y-intercepts, and use their slopes, and draw the two lines.


{{{graph(300,300,-7,7,-7,7,-3x/4+2,4x/3+5)}}}