Question 1096903
<br>An alternative to the standard algebraic solution, using logical analysis....<br>
If all 78 tickets were children's tickets, the total sales would be 78*2 = $156.<br>
The actual sales amount was $246.<br>
The difference between those two amounts is $246=$156 = $90.<br>
Each adult ticket costs $3 more than each children's ticket.<br>
So the number of adult tickets must have been 90/3 = 30.