Question 1096902
<br>If w is the width, then the length is 2 less than 3 times w:
let w = width
then 3w-2 - length<br>
The given area, 65, is length times width, so
{{{w(3w-2) = 65}}}
{{{3w^2-2w = 65}}}
{{{3w^2-2w-65 = 0}}}<br>
You can finish solving the problem by factoring; you will get one positive and one negative solution to the equation.  Of course the negative answer makes no sense in the actual problem, so choose the positive answer.<br>
And you SHOULD finish the problem that way, if this is an exercise for a class where you are learning to use algebra to solve problems like this.<br>
But if you only want the answer, it is much easier to simply look at the given area of 65 and look for two numbers whose product is 65.<br>
The only two "nice" numbers whose product is 65 are 5 and 13; and those two numbers satisfy the conditions of the problem.