Question 1096808
<pre>

Looks like you're right.  Whether by regular 
long divsion:

   <u>      x+ 2</u> 
x+9)x²+11x+21
    <u>x²+ 9x</u>
        2x+21
        <u>2z+18</u>
            3 

or by the shorter synthetic division:

-9|1 11  21
  |<u>  -9 -18</u>
   1  2   3

the remainder is 3.  In order for it to be a factor,
the remainder would have to be 0, not something else,
like, for instance, 3.

Edwin</pre>