Question 1096763
<pre><font size=5><b>
Here are all possible 52 cards:

<font color = "red">
 
A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;  J&#9829;  Q&#9829;  K&#9829; 
A&#9830;   2&#9830;   3&#9830;   4&#9830;   5&#9830;   6&#9830;   7&#9830;   8&#9830;  9&#9830;  10&#9830;  J&#9830;  Q&#9830;  K&#9830;</font>
A&#9824;   2&#9824;   3&#9824;   4&#9824;   5&#9824;   6&#9824;   7&#9824;   8&#9824;  9&#9824;  10&#9824;  J&#9824;  Q&#9824;  K&#9824;  
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;  J&#9827;  Q&#9827;  K&#9827; 

Here are the only "successful" cards:<font color = "red">
 
A&#9829;                                     9&#9829;  
A&#9830;                                     9&#9830;</font>
A&#9824;                                     9&#9824;   
A&#9827;                                     9&#9827;  

Count them! There are 8 "successful" cards out of 52 possible cards,

In probability theory, when all possibilities are equally likely,

"out of" means "over". So 8 out of 52 is a probability of 8/52 which 
reduces to 2/13.

Edwin</pre></font></b>