Question 1096705
 4x2 + 4y2 + 16x + 24y + 31 = 0

Find the center and radius of the circle. Thanks! :)
<pre>{{{4x^2 + 4y^2 + 16x + 24y + 31 = 0}}}
{{{4x^2 + 16x + 4y^2 + 24y = - 31}}}
{{{4(x^2 + 4x + y^2 + 6y) = 4(- 31/4)}}} ------- Factoring out a GCF, 4, to get leading coefficients of 1 
{{{x^2 + 4x + y^2 + 6y = - 31/4}}}
Now, complete the square on x and y. 
You will work towards getting the equation of the CIRCLE, which is in the form: {{{(x - h)^2 + (y - k)^2 = r^2}}}, where:
{{{"(h, k)"}}} = Coordinates of CENTER of circle
     {{{r}}} = Radius of the circle