Question 1096280
Let the quadratic function be {{{y = x^2+(b/a)x+(c/a)}}}


Since y-intercept is -3, therefore y = -3 for x = 0. Therefore,

{{{-3 = 0^2 + (b/a)*0 + (c/a)}}} => {{{c/a = -3}}}

Since (2,-7) is on the quadratic function (as this is the vertex), for x= 2, y must be equal to -7

{{{-7 = 2^2+2(b/a)-3}}} => {{{b/a = -4}}}

Therefore, the function is {{{y = x^2 -4x -3}}}