Question 1096264
1.Let w and w+6 be the width and the length of the picture, respectively. Then, the frame would be w+6 by w+12. So:
(w+6)(w+12)-(w)(w+6)=288
Solve for w
2. Let n be the amount that both dimensions need to be increased. Then:
(12+w)(8+w)=2(12)(8)=192
w²+20w+96=192
w²+20w-96=0
Solve for w
3.Let n be the first integer. Then, the second would be n+1. So:
n(n+1)=210
n²+n-210=0
Solve for n
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