Question 1096276
Distance = Speed * Time

Assuming that distance traveled in one way trip is D and time taken for the onward and return journey is T1 and T2, then

Since the distance traveled in both onward and return journey is same, we can say D = 245 * T1 = 265 * T2 ____________(1)

Also we know that the Time taken in first journey was 2 hours longer than the return journey, therefore

T1 - T2 = 2 or T1 = T2 + 2 ___________(2)

Substituting value T1 in equation (1), we will get 

245* (T2+2) = 265 * T2 => 20*T2 = 490 => T2 = 24.5 hrs or 24 hrs and 30 mins