Question 1096161
x varies jointly with "b" and the square of "c".
{{{x = b*c^2}}}
 If x = 270 when b = 6 and c = 3,
{{{270 = K * 6 * 3^2}}}find k
270 = 54k
k = 270/54
k = 5
therefore the equation is
{{{x = 5b*c^2}}}
 find x when b = 10 and c = 4.
x = 5*10*4^2
x = 800