Question 1095952
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{{{ (ln x)^2 + 2*(ln x) = 3 }}}
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<pre>
{{{(ln(x))^2}}} + {{{2*(ln x)}}} = 3   ====>

{{{(ln(x))^2}}} + {{{2*(ln x)}}} + 1 = 4   ====>

{{{(ln(x)+1)^2}}} = 4  ====>

ln(x) + 1 = +/- 2  ====>


Case a):  ln(x) + 1 = 2  ====>  ln(x) = 1  ====>  x = e.


Case b):  ln(x) + 1 = -2  ====>  ln(x) = -3  ====>  x = {{{e^(-3)}}}.


<U>Answer</U>.  There are two solutions:  x = e   and   x = {{{e^(-3)}}}.
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