Question 1095853
x^2+x+6=0
look at the discriminant of the sqrt (b^2-4ac)=sqrt(1-24) or sqrt(-23).  This has no real solutions.  If c is large positive, a is small and b is small, b^2-4ac will probably be negative.
{{{graph(300,300,-10,10,-10,10,x^2+x+6)}}}