Question 14140
x+y+z = 30000 --eqn1


0.02x + 0.03y + 0.06z = 1110 --eqn2


0.03y = 0.02x + 150 --eqn3


OK... multiply eqn 1 by 0.06 then subtract eqn2, leaving 0.04x + 0.03y = 690 --eqn4


Now rearragne eqn3 around and then add it to eqn4, giving x = 9000.


Then find y and z as per the other Q.


jon.