Question 1095668
(6x^3/3x^2-27):(42/3-x)
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If you mean
6x^3/(3x^2-27)/(42/(3-x))
{{{ 6x^3/(3x^2-27)/(42/(3-x)) }}}
= {{{2x^3/(x^2-9)/(42/(3-x))}}}
= {{{-x^3/((x-3)*(x+3))/(21/(x-3))}}}
= {{{-x^3/(x+3)/21}}}