Question 1095684
solve the following equation for real numbers x and y.
{{{((1+i)/(1-i))^2 + 1/(x+iy) = 1+i}}}
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{{{((1+i)/(1-i))^2 = (1+i)^2/(1-i)^2 = (2i/-2i) = -1}}}
--> {{{-1 + 1/(x+iy) = 1+i}}}
{{{1/(x+iy) = 2+i}}}
Invert
{{{x+iy = 1/(2+i) = (2-i)/5}}}
x = 2/5, y = -1/5