Question 1095673
You showed one pair of parentheses to group an expression, so if the equation is written exactly the way given to you,


{{{x-5/x+3=2(x+1)/x+3}}}

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multiply left and right by x;

{{{x^2-5+3x=2(x+1)+3x}}}

{{{x^2-5=2(x+1)}}}

{{{x^2-5=2x+2}}}

{{{x^2-2x-5-2=0}}}

{{{x^2-2x-7=0}}}

not factorable so {{{x=(2+- sqrt(4+4*7))/2}}}

{{{x=(2+- 2*sqrt(8))/2}}}

{{{highlight(x=1+- sqrt(8))}}}