Question 1095664
<br>If a polynomial has real coefficients, then complex roots occur in conjugate pairs.  So if 1+i is a root, then 1-i is another root.  So the three roots are 1+i, 1-i, and 10.  Then the polynomial is
{{{(x-(1+i))(x-(1-i))(x-10)}}}
{{{((x-1)-i)((x-1)+i)(x-10)}}}
{{{(x^2-2x+1+1)(x-10)}}}
{{{(x^2-2x+2)(x-10)}}}
{{{x^3-10x^2-2x^2+20x+2x-20}}}
{{{x^3-12x^2+22x-20}}}