<PRE><B>Question 1095645</B>
We use the binomial probaility distribution to answer this problem
:
Probability(P) (k successes out of n trials) = nCk * p^k * (1-p)^(n-k) where p is probability of a success and nCk - n! / (k! * (n-k)!)
:
p = 1/4 = 0.25
:
P (5 successes out of 5 trials) = (5! / (5! * (5-5)!) * (0.25)^5 * (1-0.25)^(5-5) =
:
1 * (0.25)^5 * 1 = 0.000976562 approximately 0.001
:
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