Question 1095583
Find two consecutive integers such that 1/2 times the first added to twice the second sums to 57. 
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n and n+1, these integers


{{{n/2+2(n+1)=57}}}


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{{{n+4(n+1)=114}}}


{{{n+4n+4=114}}}


{{{5n=110}}}


{{{n=22}}}


The two consecutive integers:  22 and 23