Question 1095542
<br>Rewrite the 32 as 2 to the 5th power; and rewrite the 7th root as a fractional power:<br>
{{{((2)^5*(x)^(5/7))^(-1/5)}}}<br>
Then use the power-of-a-power rule of exponents:
{{{(2)^(-1)*(x)^(-1/7)}}}<br>
Then if "simplest form" means no negative exponents:
{{{1/((2)^x*(x)^(1/7))}}}