Question 1095516
<br>If the polynomial has real coefficients, then complex or imaginary roots must occur in conjugate pairs.  So if i is a root, -i is another root.<br>
That makes the three roots -3, i, and -1; the polynomial is of the form
{{{f(x) = a(x+3)(x-i)(x+i)}}}
where a is a constant.<br>
The value of the constant a is determined using the given information that f(1) is 8.  So to find the value of a and thus finish finding the exact polynomial, solve the equation f(1) = 8:
{{{a(1+3)(1-i)(1+i) = 8}}}<br>
I'll let you finish from there....