Question 1095490
Dimensions are  4w-5 and w.


You can model the area just based on the width, w.
{{{highlight(w(4w-5)=9)}}}

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{{{4w^2-5w-9=0}}}
discr, {{{25+16*9=169=13^2}}}
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{{{w=(5+- 13)/8}}}
{{{w=(5+13)/8=18/8}}}
{{{w=9/4}}}
{{{highlight(w=2&1/4)}}}
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{{{highlight(length=4)}}}